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Post Reply Trees in da Forest
Posted 9/14/08

dreems-girl wrote:

ya sry 4 skiping ur Q ren kun


its ..... okay
Posted 9/14/08
ill give you hints tomorrow
Posted 9/14/08

kurosakiichigokun wrote:

ok every 1 can answer this Q so ignore wat she said guys
& ya dont forget renfiiel's Q guys

get lost lee ya dont 4get abt ren kun's Q

Posted 9/14/08 , edited 9/15/08

kurosakiichigokun wrote:

sorry again man oi boso i'm leavin now sleep with the answer sweety & u can eat it if u want


hahahah ne lee i thought abt it since there is 2 barbers shops in town & of course they can't cut their own hair so i think that the first barber went 2 the 2nd 2 have a nice cut hair as long as there r just 2 barbers so the first barber cut he's hair & make it nice & kawaiii & the 1st barber
went 2 the 2nd 2 have a haircut 2 but the haircut wasn't good as the 2nd it was messy so that's Y he went 2 the 1st barber & have his haircut
so is it right ?? if it is u will say that word again 2 me hahhahhah
Posted 9/15/08

dreems-girl wrote:


kurosakiichigokun wrote:

sorry again man oi boso i'm leavin now sleep with the answer sweety & u can eat it if u want


hahahah ne lee i thought abt it since there is 2 barbers shops in town & of course they can't cut their own hair so i think that the first barber went 2 the 2nd 2 have a nice cut hair as long as there r just 2 barbers so the first barber cut he's hair & make it nice & kawaiii & the 1st barber
went 2 the 2nd 2 have a haircut 2 but the haircut wasn't good as the 2nd it was messy so that's Y he went 2 the 1st barber & have his haircut
so is it right ?? if it is u will say that word again 2 me hahhahhah


i think you are rigght!! ^^
hehe you answered it correct!! i hope :P

Posted 9/15/08
Okay i will give you hints to my question now :)

B(t)=C*e^(gt-0.5st²)

1st Derivative:
B'(t)=C*(g-st)*e^(gt-0.5st²)

2nd Derivative:
B''(t)=C* (g-st)(g-st)*e^(gt-0.5st²)+-s*e^(gt-0.5st²)
B''(t)=C* (g-st)²*e^(gt-0.5st²)+-s*e^(gt-0.5st²)
B''(t)=C* e^(gt-0.5st²) * ((g-st)²-s)

The root of the first derivative is the peak of the function (maximum).
(The point with the highest number of trees)

B'(t)!=0

e^(gt-0.5st²) can never be = 0

so

(g-st) has to become 0
g-st=0
g=st
t=g/s
t=0.1/0.01
t=10

so: in year 10 there is the highest number of trees (2010)

okay i think you should be able to do the rest now^^
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Posted 9/17/08
wow its a quiet nice a question i like it hahaha well i will TRY to answer it but it might take a long dude i got skool and stuff but i will try to answer it good question i love it XD good job dude hmmm i need to think first the main equation hmmm i will work on it right away XD
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Posted 9/17/08
hey!! it seems..too good!! n intresting but!! i will answer it later..coz i lil bit did not understand the question eheh!!i will post my answer once i finised okey marc*.*
Posted 9/17/08

punkforever wrote:

hey!! it seems..too good!! n intresting but!! i will answer it later..coz i lil bit did not understand the question eheh!!i will post my answer once i finised okey marc*.*


okay thats cool^^ if there are any questions just ask
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Posted 9/17/08
arigatuo^.^ marc^.^ but u have wait for while ehehe^.^
Posted 9/19/08
nuthings happening... so i think im gonna solve it for you guys now^^
Posted 9/19/08
well because of a threat on my life by a certain person i wont solve it today
Posted 9/19/08 , edited 9/19/08

Renfiel wrote:

well because of a threat on my life by a certain person i wont solve it today

promiss me u wont solv it till non of us know the answer or till i ask u 2 do it ahooooooooooooooo

now the promiss hahahh
Posted 9/19/08
i promise you i wont solve it for at least x hours!! xD hahaha

2(x^3)=746496

now solve that
Posted 9/19/08

Renfiel wrote:

i promise you i wont solve it for at least x hours!! xD hahaha

2(x^3)=746496

now solve that


is that another Q ???
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