I can't find the other thread.

But, 0.99 recurring does equal 1. I asked a Maths doctorate and he confirmed that although there are more convincing proofs and conjectures, this one below (Forgot who did it, but whoever it was, you're right):

Let's say .9 repeating is x and I'll will write as just .99R

Start:

.99R = x

9.99R = 10x

9.99R - .99R = 10x - x

9 = 9x

1 = x

x = .99R

THEREFORE, .99R is equal to 1!!!

Is actually quite sound.