**Do the Math
^no math here




^ there's an english here. without math, you'll never learn you insect. numbers are math, these numbers of pages are math, that age of urs is math, that crunchyroll points of urs are math. you will never know that i am the one who rule XD
ok here's mine, its just a distance problems so its not that very difficult to answer: Mr. Honda and Mr. Toyota arrange to meet on the highway connection their hometowns. Mr. Honda drives at 45 kph and Mr. Toyota at 35 kph. They leave their houses which are 120 km apart at the same time. In how many hours will they meet? :w00t: very very easy!!! 



Find the solution wahehe
1. [x + y sin (y/x)]dx  x sin (y/x)dy = 0 clue use homogenous diff equation... hehe 

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ichi_ni240 wrote: ok here's mine, its just a distance problems so its not that very difficult to answer: Mr. Honda and Mr. Toyota arrange to meet on the highway connection their hometowns. Mr. Honda drives at 45 kph and Mr. Toyota at 35 kph. They leave their houses which are 120 km apart at the same time. In how many hours will they meet? :w00t: very very easy!!! That would be 1.5 hours, seeing as they are travelling at 80kmph in total and need to travel 120km in total And; [x + y sin (y/x)]dx  x sin (y/x)dy = 0 having done a page of working i have; (x/y) = 2sin(x) or y = x/(2 sin(x)) PM me to say whether I'm correct which is smaller; 2 or +1? 

N/A


+1
cosin 75 degrees show me da solution very easy no calcu pls XD 



0.26? henz_lan wrote: ichi_ni240 wrote: ok here's mine, its just a distance problems so its not that very difficult to answer: Mr. Honda and Mr. Toyota arrange to meet on the highway connection their hometowns. Mr. Honda drives at 45 kph and Mr. Toyota at 35 kph. They leave their houses which are 120 km apart at the same time. In how many hours will they meet? :w00t: very very easy!!! That would be 1.5 hours, seeing as they are travelling at 80kmph in total and need to travel 120km in total And; [x + y sin (y/x)]dx  x sin (y/x)dy = 0 having done a page of working i have; (x/y) = 2sin(x) or y = x/(2 sin(x)) PM me to say whether I'm correct which is smaller; 2 or +1? Wrong!! nid to use this y=vx dy= xdx+xdv use integration and differential after some solution you shoul get this answer ln[x] + cos (x/y)=lnc ill pm you the solution 

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i think it's 1.1
here's mine 9.4 divide 6.9 = 



oh god cant believe theres a maths thread.
seems i cant get away from all the maths whizzes flying around these days 



thank god its an easy one
1.362 (3 deci ap standard) > 10!=? 



3628800
Find the particular solution which satisfies the given boundary condition in each of the following differential equation a) x y (1 + x^2) dy/dx = 2 + y^2 ; y(1) = 0 b) dy/dx + y/x = cos 2x ; y(PI) = 0 d) dy/dx  y cotx = tan ^2 x ; y(PI/4) = 0 this solution would be so long... 



what, can anyone answer mine






a) x y (1 + x^2) dy/dx = 2 + y^2 ; y(1) = 0
[y/(2 + y^2)] dy = dx/[x(1 + x^2)] Integral [y/(2 + y^2)] dy = Integral dx/[x(1 + x^2)] (1/2) Ln (2 + y^2) = Integral dx/[x(1 + x^2)] 1/[x(1 + x^2)] = 1/x  x/(1 + x^2) (1/2) Ln (2 + y^2) = Integral dx/[x(1 + x^2)] = Ln x  (1/2) Ln (1 + x^2) + c (1/2) Ln (2 + y^2) = (1/2) [2 Ln x  Ln (1 + x^2)] + c Ln (2 + y^2) = 2 Ln x  Ln (1 + x^2) + C Ln (2 + y^2) = Ln [x^2 /(1 + x^2)] + C e^[Ln (2 + y^2)] = e^[Ln [x^2 /(1 + x^2)] + C] 2 + y^2 = A x^2 /(1 + x^2) y(1) = 0 2 + 0 = A 1/(1 + 1) 2 = A/2 A = 4 y^2 = 4x^2/(1 + x^2)  2 y = sqrt(4x^2/(1 + x^2)  2) b) dy/dx + y/x = cos 2x ; y(PI) = 0 x dy/dx + y = x cos 2x (d/dx) (xy) = x cos 2x xy = integral (x cos 2x) dx xy = (1/2) x sin (2x)  (1/2) Integral (sin 2x) dx xy = (1/2) x sin 2x + (1/4) cos 2x + c y(pi) = 0 0 = (1/2) pi * 0 + (1/4) (1) + c c = 1/4 y = (1/2) sin 2x + (1/(4x)) cos 2x  1/(4x) d) dy/dx  y cotx = tan ^2 x ; y(PI/4) = 0 I think that  y cot x should be + y cot x sin x dy/dx + y cos x = (sin x)^3 / (cos x)^2 (d/dx) (y sin x) = (1  (cos x)^2) sin x / (cos x)^2 y sin x = Integral (sin x/ (cos x)^2  sin x) dx y sin x = 1/(cos x) + cos x + c y(pi/4) = 0 0 = 1/(sqrt(2)/2) + sqrt(2)/2 + c 0 = sqrt(2) + sqrt(2)/2 + c 0 = (3/2) sqrt(2) + c c = (3/2) sqrt(2) y = 1/( sin x cos x) + cot x  (3/2) sqrt(2) /sin x y = csc x sec x + cot x  (3/2) sqrt(2) csc x <_< nobody won't answer! 9! = ? 



9 x 8 x 7 x 6 x 5 x 4 3 x 2 i needa start my Maths for Comp Science shit.... it's too hard ! 

member since FOREVER


calculus is my worst subject right now
9!=362880 which step is wrong? a=b plus a 2a=a+b minus 2 b 2a2b=ab factor 2(ab)=(ab) simplify 2=1 

